Equation 3 is: d=V1Δt+½aΔt²
and...
there are two standard points in the graph (t1, v1) and (t2, v2).
To determine the displacement (d), we are required to calculate the area between the slope and the x-axis, and there are two sections for this. The first one (lower one) is a rectangle and the second one is a triangle.
Coincidently, there are two parts for equation 3 as well. v1Δt and ½aΔt².
The area of a rectangle is defined by the formula Base x Height, where the height is v1 and the base is t2-t1.
A = v1(t2-t1)
A = v1(Δt)
The area of a triangle is defined by the formula Base x Height / 2. As we learned earlier, base is represented by Δt, and the height in this case is v2-v1. Also, from equation 1, v2-v1=aΔt.
A = ½Δt(v2-v1)
A = ½ΔtaΔt
A = ½aΔt²
Thus, d=vΔt+½aΔt²
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